Rhode Island among three top Obama states
This won’t come as any surprise, but Rhode Island is once again a deep, cobalt Blue state in presidential politics. President Obama’s margin in the Ocean state appears to be the third highest in the nation, after Hawaii (the president’s birthplace, unless you believe Donald Trump) and Vermont, which was once the most Republican state in the U.S.
Obama won Hawaii by 42.7 percent of the vote, took Vermont by 35.8 percent and crushed Republican Mitt Romney in Rhode Island by 27.9 percentage points. After Rhode Island came New York, where the president triumphed by a 26.8 percent margin.
The calculations come from the Washington Post. These numbers are fairly consistent with where Rhode Island voters have landed in recent elections. In 1960, Rhode Island was John F. Kennedy’s best state and the Ocean State has not supported a Republican presidential candidate since the 49-state Ronald Reagan landslide of 1984. (Democrat Walter Mondale carried only his home state of Minnesota in that election). Rhode Island also supported Richard Nixon, a Republican, against Democrat George McGovern in 1972, which was another 49-state crushing for the GOP. McGovern won only Massachusetts that year.
The six New England states continue to be the Democratic Party’s hardest base in presidential elections. Since 1992, the Democratic presidential aspirant has won every New England state in every election, with the exception of New Hampshire in 2000, where George W. Bush defeated Democrat Al Gore by about 7,000 votes in an election where Granite State voters cast 25,000 votes for third party candidate Ralph Nader.